20x^2=5x

Solution for 20x^2=5x equation:

20x^2=5x

We move all terms to the left:

20x^2-(5x)=0

a = 20; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·20·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*20}=\frac{0}{40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*20}=\frac{10}{40}
=1/4
$